我有两个场景,我必须找到基于参数的结果(通过交叉乘法)。
例如
场景-1:
int previousConceptCount = 100
int currentConceptCount = 20
int previousTime = 10
int currentTime = ?
Que: If 100 concepts take 10 mins to complete than how much time 20 concepts will take?
Ans:
currentTime = (currentConceptCount * previousTime) / previousConceptCount //Works fine
//Mathematical calculation which I've added in code.
100 10
----- = ----- ==> x = (20(currentConceptCount) * 10(previousTime)) / 100(previousConceptCount)
20 x
场景-2:
int previousConceptCount = 10
int currentConceptCount = 100
int previousDocumentCount = 100
int currentDocumentCount = 100
int previousTime = 10
int currentTime = ?
Que: If 10 concepts with 100 documents take 10 mins than how much time 100 concepts with 100 documents will take?
Ans:
currentTime = ?
在这种情况下如何计算currentTime
。我总是有conceptCounts(both previous and current)
和documentCounts(both previous and current)
,并在此基础上找到时间。我不知道需要什么数学公式,或者让我这样说,我不知道在这种情况下如何计算。
有什么建议吗?
您只需要将您的概念乘以您的文档:
(20(currentConceptCount*currentDocumentCount) * 10(previousTime)) / 100(previousConceptCount*previousDocumentCount)
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